Question: Write down the equation of motion for a charged particle in uniform, parallel electric and magnetic fields, both in the z-direction, and solve it, given that the particle starts from the origin with the velocity
. A screen is placed at x=a where
. Show that the locus of points of arrival of particles with given m and q, but different speeds
, is approximately a parabola.
Answer: The equation of motion is given by the Lorentz Force equation:

However, since
and
for this problem, the equation of motion becomes

which reduces to

First, lets solve
. If we integrate
, we get

, this means
. Therefore,
.
If we integrate again, we get:

, this means
. Therefore,
.
Next, we will reduce the other two equations


, therefore
.We can similar reduce 

, therefore
.If we put these equations into the original equations of motion, we can decouple the x and y terms.

which has a general solution of

However, since
, therefore
.
In order to calculate A, we need to take the derivative.

, the following reduction can be made
. Therefore,
and
.
Also, since
, we can solve for y


This means the equation of motion is:






Last weekend I went to VanLan 2007! If you haven’t heard of it, I am sure you are not alone. Every year all my old High School friends go to Vancouver to play computer games and hang-out with each other. It is a good way to stay connected with each other. This year there was only about a dozen of us (a lot less from last year), but it was still a lot of fun. The only down-fall of VanLan is that every year there seems to be more drinking and less computer games. I guess it would be less of an issue if I was a bigger drinker. However, on the positive side, it is a lot easier to beat an intoxicated opponent. Even with this set-back, we did play a lot of computer games. Here is an overview of some of the games we played: 